# Inverse Transforms MCQ’s

This set of Network Theory Multiple Choice Questions & Answers (MCQs) focuses on “Inverse Transforms”.

1. For the function F (s) = (s2+s+1)/s(s+5)(s+3), after splitting this function into partial fractions, the co-efficient of 1/(s+5) is?
a) 1.1
b) 2.1
c) 3.1
d) 4.1

2. For the function F (s) = (s2+s+1)/s(s+5)(s+3), after splitting this function into partial fractions, co-efficient of 1/(s+3) is?
a) -1.17
b) 1.17
c) -2.27
d) 2.27

3. For the function F (s) = (s2+s+1)/s(s+5)(s+3), after splitting this function into partial fractions, the co-efficient of the term 1/s is?
a) 1/5
b) 1/10
c) 1/15
d) 1/20

4. For the function F (s) = (s2+s+1)/s(s+5)(s+3), after splitting this function into partial fractions. Find the partial fraction expansion of the function.
a) 1/15s-2.1/(s+5)+1.17/(s+3)
b) 1/15s-2.1/(s+5)-1.17/(s+3)
c) 1/15s+2.1/(s+5)+1.17/(s+3)
d) 1/15s+2.1/(s+5)-1.17/(s+3)

5. For the function F (s) = (s+5)/s(s2+2s+5), after splitting this function into the partial fractions, the co-efficient of 1/(s+1-j2) is?
a) 1/2
b) -1/2
c) 1/4
d) -1/4

6. For the function F (s) = (s+5)/s(s2+2s+5), after splitting this function into the partial fractions. What is the expression of F (s) after splitting into partial fractions is?
a) 1/s-1/2(s+1-j2) -1/2(s+1+j2)
b) 1/s+1/2(s+1-j2) -1/2(s+1+j2)
c) 1/s+1/2(s+1-j2) +1/2(s+1+j2)
d) 1/s-1/2(s+1-j2) +1/2(s+1+j2)

7. For the function F (s) = (s+5)/s(s2+2s+5), after splitting this function into the partial fractions, 1/s co-efficient is?
a) 1
b) 2
c) 3
d) 4

8. For the function F (s) = (s+5)/s(s2+2s+5), after splitting this function into the partial fractions, determine the co-efficient of 1/(s+1-j2)?
a) -1/4
b) 1/4
c) -1/2
d) 1/2

9. For the function F (s) = (s+5)/s(s2+2s+5), after splitting this function into the partial fractions. What is the inverse transform of F (s) is?
a) 1+ 1/2 e(-1+j2)t-1/2 e(-1-j2)t
b) 1+ 1/2 e(-1+j2)t+1/2 e(-1-j2)t
c) 1- 1/2 e(-1+j2)t-1/2 e(-1-j2)t
d) 1- 1/2 e(-1+j2)t+1/2 e(-1-j2)t

10. The inverse transform of the function k/(s+a) is?
a) ke-at u(t)
b) keat u(t)
c) ke-at u(t-a)
d) keat u(t-a)