Miller Compensation and Pole Splitting MCQ’s

Electronic Devices & Circuits Electronics & Communication Engineering

This set of Electronic Devices & Circuits Multiple Choice Questions & Answers (MCQs) focuses on “Miller Compensation and Pole Splitting”.

1. Which law is the Miller compensation and pole splitting based on?
a) Ohm’s Law
b) Moore’s Law
c) Coulomb’s Law
d) Kirchhoff’s Current and Voltage Law

2. According to Millers compensation, what should be the configuration of voltages?
a) Both dependent voltages
b) Both independent voltages
c) One dependent voltage and one independent voltage
d) No specification necessary

3. What technique is used in Millers compensation?
a) Two – port network
b) Hybrid parameters
c) Grounding
d) Short circuiting

4. What is the impedance from the input port according to Millers compensation and pole splitting?
a) Zin1 = Z × K / 1 – K
b) Zin1 = Z × K / 1 + K
c) Zin1 = Z / 1 – K
d) Zin1 = Z / 1 + K

5. According to Millers compensation and pole splitting, what is the impedance in input port if I1 = 20 mA, I2 = 30 mA and Z = 2.3 kΩ?
a) 0.38 kΩ
b) 3.83 kΩ
c) 0.57 kΩ
d) 5.75 kΩ

6. What are the applications of Millers compensation and pole splitting?
a) Lower power consumption
b) Additional voltage source
c) Additional current source
d) Circuit optimization

7. What is the impedance from the output port according to Millers compensation and pole splitting?
a) Zin2 = Z × K / K – 1
b) Zin2 = Z × K / K + 1
c) Zin2 = Z / K – 1
d) Zin2 = Z / K + 1

8. According to Millers compensation and pole splitting, what is the impedance in output port if I1 = 20 mA, I2 = 30 mA and Z = 2.3 kΩ?
a) 0.38 kΩ
b) 3.83 kΩ
c) 0.57 kΩ
d) 5.75 kΩ

9. Millers compensation and pole splitting is used in the high – frequency analysis of BJTs and FETs.
a) True
b) False

10. How do we calculate Millers capacitance when aV = 250 and C = 9.90pF?
a) 2.485pF
b) 2.485nF
c) 24.85pF
d) 24.85nF

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