# Sinusoidal Response of an R-L Circuit MCQ’s

This set of Network Theory Multiple Choice Questions & Answers (MCQs) focuses on “Sinusoidal Response of an R-L Circuit”.

1. The particular current obtained from the solution of i in the sinusoidal response of R-L circuit is?

a) i_{p} = V/√(R^{2}+(ωL)^{2}) cos(ωt+θ+tan^{-1}(ωL/R))

b) i_{p} = V/√(R^{2}+(ωL)^{2}) cos(ωt+θ-tan^{-1}(ωL/R))

c) i_{p} = V/√(R^{2}+(ωL)^{2}) cos(ωt-θ+tan^{-1}(ωL/R))

d) i_{p} = V/√(R^{2}+(ωL)^{2}) cos(ωt-θ+tan^{-1}(ωL/R))

2. The value of ‘c’ in complementary function of ‘i’ is?

a) c = -V/√(R^{2}+(ωL)^{2}) cos(θ+tan^{-1}(ωL/R))

b) c = -V/√(R^{2}+(ωL)^{2}) cos(θ-tan^{-1}(ωL/R))

c) c = V/√(R^{2}+(ωL)^{2}) cos(θ+tan^{-1}(ωL/R))

d) c = V/√(R^{2}+(ωL)^{2}) cos(θ-tan^{-1}(ωL/R))

3. In the sinusoidal response of R-L circuit, the complementary function of the solution of i is?

a) i_{c} = ce^{-t(R/L)}

b) i_{c} = ce^{t(RL)}

c) i_{c} = ce^{-t(RL)}

d) i_{c} = ce^{t(R/L)}

4. The complete solution of the current in the sinusoidal response of R-L circuit is?

a) i = e^{-t(R/L)}[V/√(R^{2}+(ωL)^{2}) cos(θ-tan^{-1})(ωL/R))]+V/√(R^{2}+(ωL)^{2}) cos(ωt+θ-tan^{-1})(ωL/R))

b) i = e^{-t(R/L)}[-V/√(R^{2}+(ωL)^{2}) cos(θ-tan^{-1})(ωL/R))]-V/√(R^{2}+(ωL)^{2}) cos(ωt+θ-tan^{-1})(ωL/R))

c) i = e^{-t(R/L)}[V/√(R^{2}+(ωL)^{2}) cos(θ-tan^{-1})(ωL/R))]-V/√(R^{2}+(ωL)^{2}) cos(ωt+θ-tan^{-1})(ωL/R))

d) i = e^{-t(R/L)}[-V/√(R^{2}+(ωL)^{2}) cos(θ-tan^{-1})(ωL/R))]+V/√(R^{2}+(ωL)^{2}) cos(ωt+θ-tan^{-1})(ωL/R))

5. In the circuit shown below, the switch is closed at t = 0, applied voltage is v (t) = 100cos (103t+π/2), resistance R = 20Ω and inductance L = 0.1H. The particular integral of the solution of ‘i_{p}’ is?

a) i_{p} = 0.98cos(1000t+π/2-78.6^{o})

b) i_{p} = 0.98cos(1000t-π/2-78.6^{o})

c) i_{p} = 0.98cos(1000t-π/2+78.6^{o})

d) i_{p} = 0.98cos(1000t+π/2+78.6^{o})

6. The current flowing through the circuit at t = 0 in the circuit shown below is?

a) 1

b) 2

c) 3

d) 0

7. In the circuit shown below, the switch is closed at t = 0, applied voltage is v (t) = 100cos (103t+π/2), resistance R = 20Ω and inductance L = 0.1H. The complementary function of the solution of ‘i’ is?

a) i_{c} = ce^{-100t}

b) i_{c} = ce^{100t}

c) i_{c} = ce^{-200t}

d) i_{c} = ce^{200t}

8. In the circuit shown below, the switch is closed at t = 0, applied voltage is v (t) = 100cos (103t+π/2), resistance R = 20Ω and inductance L = 0.1H. The complete solution of ‘i’ is?

a) i = ce^{-200t} + 0.98cos(1000t-π/2-78.6^{o})

b) i = ce^{-200t} + 0.98cos(1000t+π/2-78.6^{o})

c) i = ce^{-200t} + 0.98cos(1000t+π/2+78.6^{o})

d) i = ce^{-200t} + 0.98cos(1000t-π/2+78.6^{o})

9. In the circuit shown below, the switch is closed at t = 0, applied voltage is v (t) = 100cos (103t+π/2), resistance R = 20Ω and inductance L = 0.1H. The value of c in the complementary function of ‘i’ is?

a) c = -0.98cos(π/2-78.6^{o})

b) c = -0.98cos(π/2+78.6^{o})

c) c = 0.98cos(π/2+78.6^{o})

d) c = 0.98cos(π/2-78.6^{o})

10. In the circuit shown below, the switch is closed at t = 0, applied voltage is v (t) = 100cos (103t+π/2), resistance R = 20Ω and inductance L = 0.1H. The complete solution of ‘i’ is?

a) i = [-0.98 cos(π/2-78.6^{o})] exp(-200t)+0.98cos(1000t+π/2-78.6^{o})

b) i = [-0.98 cos(π/2-78.6^{o})] exp(-200t)-0.98cos(1000t+π/2-78.6^{o})

c) i = [0.98 cos(π/2-78.6^{o})] exp(-200t)-0.98cos(1000t+π/2-78.6^{o})

d) i = [0.98 cos(π/2-78.6^{o})] exp(-200t)+0.98cos(1000t+π/2-78.6^{o})